class TestProject8{ public static void Main(string[] args) { int value; if (true) { value = 10; Console.WriteLine($"Inside the code block: {value}"); } Console.WriteLine($"Outside the code block: {value}"); }}
class TestProject8{ public static void Main(string[] args) { int value; if (true) { value = 10; Console.WriteLine($"Inside the code block: {value}"); } Console.WriteLine($"Outside the code block: {value}"); }}
explanation given by the course
"For the second code sample, the complier concludes that the contents of the if statement code block will always be executed (true is always true). The compiler doesn't generate a build error because it interprets the second code sample to have a single execution path as follows:
int value; value = 10; Console.WriteLine($"Inside the code block: {value}"); Console.WriteLine($"Outside the code block: {value}");
int value; value = 10; Console.WriteLine($"Inside the code block: {value}"); Console.WriteLine($"Outside the code block: {value}");
"
QUESTION:
I don't really understand the reasoning behind this one. please help me understand.
how can a variable be initialized inside an if statement, then accessing the variable not being an issue because, well, there is just one possible execution path?
Extra:
code sample 1
class TestProject8{ static void Main(string[] args) { bool flag = true; int value; if (flag){ value = 10; Console.WriteLine($"Inside the code block: {value}");}Console.WriteLine($"Outside the code block: {value}"); }}
class TestProject8{ static void Main(string[] args) { bool flag = true; int value; if (flag){ value = 10; Console.WriteLine($"Inside the code block: {value}");}Console.WriteLine($"Outside the code block: {value}"); }}