38 Replies
@Gyro Gearloose
Note for OP
+solved @user1 @user2... to close the thread when your doubt is solved. Mention the users who helped you solve the doubt. This will be added to their stats.@hardcoreisdead
dekhta hu
A is wrong
B aa gya
C ka idk kaise check karu
@Prasan koi quantity thi kya E/sigma
??
plate ka area kya lu woh nhi samjh aa rha
E= sigma/E0 hota tha
Itna yaad ha mereko
A aur B bhi kese nikale
@hardcoreisdead
E= V/d1
Ye aya tha ab mai isme vo sigma 1 and 2 kaha se laun
img ni aa ri bc
oh sorry galat thread mei daldi
,rotate
Shit
Aagya yaad
padhai karte hue "teri yaadein" sunoge toh yhi hoga
o bc lagta hai phy ki yaadein hai 💀
Vo mai ni sunra laptop pe spotidy chalara koi😅
oh lol
anyways
kya yaad aaya
ðŸ˜
Paper mei kardia tha ab nahi horaha tha, vo yaad aya
Anyways
C kaise aayega lala
C is correct right
Nah ig ek hi sahi tha isme
B option
anyways C kaise check hoga
Vahi to main puchraha hun
ill ask some ppl
Alr
Integralofe2x ko tag kardun?
wait i am trying
Alr
karde waise kya hi jaa rha
@integralofe^2v
@Real potato
@Prasan tune emi padha hai na
doubts dekhle mere bhai
Kar to lia ha
Practice km ha par koina dekhta
basically capacitors series me honeg and charge distribution kuch aise hoga then hame total charge batana in middle plate and since they are connected ( i have drawn them far so they clearly visible) but middle plate is same so uspe charge q2-q1 ayega so ig there will be a neg sign instead of positive so C is wrong ig
How do u get q2-q1
i showed how to get q1 ( u can convert it in sigma since que asks for tht) and u can follow same steps to find q2 and subtract them
and also this may seem misleading but this aint a RC circuit i js showed the resistors which are INFUSED in the capcitor
sigma is surface charge density
Lol yhi post karne aayatha
Did the same as u
nice im doing emi rn will come to the doubt after i complete it
Ok I read your method and mine is way different
Gives it in 1 line
Ok so C would've been correct if the two quantities were subtracted and multiplied by epsilon
@integralofe^2v
oh yea frgt abt epsilon naught but yea ig they shud be subtracted
Oh ye bhi badhia ha
+solved @integralofe^2v @CorrodedCoffin
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