friedel-crafts alkylation
Shouldn't both a and d be correct in this? Aniline won't undergo friedel crafts cuz it undergoes what acid base rxn? The given ans is solely d.
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@Dexter
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FC rxn deactivated ring pr ni hoti
Ph-COOH m COOH is e-withdrawing grp
Ah okay..
So it doesn't undergo friedel-crafts, right? Cuz it'll react like this
yeah ik that.. i was asking shouldnt both a and d be right
Denge saare options hi kharab
But aniline is particularly bad
Okay yeah.. they gave only opt d as the ans, so I was confused
thankss
+solved @Enamine
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