39 Replies
@Gyro Gearloose
Note for OP
+solved @user1 @user2... to close the thread when your doubt is solved. Mention the users who helped you solve the doubt. This will be added to their stats.im getting a2= m1gsinqcosq/(m2cos^2q+m1sin^2q)
$$\frac{m_1gsin\theta cos\theta}{m_2 cos^{2} \theta+m_1 sin^{2} \theta}$$
Real potato
@CorrodedCoffin can you check?
yes mera bhi yhi a2 aa rha hai
m1a1sinq = m1g - Ncosq
Nsinq = m2a2
a1cos = a2
in teen se aagya
btw is Ncosq = m2g ??
a1=a2tantheta
aisa hi direction h
oh shoot sry..
hain fir kaise shi aa gya mera
yaar cos mein hi aana chahiye
agar m2 x dist peeche jayega toh m1 y dist along the incline slide karega
cos =x/y
a1cosq = a2
wait what
u should be writing the constraint eqn perpendicular to common surface no
surface ke parallel hi a2 hai so perpendicular mein kya loge
Are these the correct eqns?
@CorrodedCoffin bhaiya?
,rotate
nope
Correct wali dm par samjha do pls🙏🏻
a1 ka acc bhi to hai aage ki side
Uska kuch component aayega na surface ke along
Waha se hi relation aya hai
Ye wla
Mene a1 - y axis me lia hai
Downwards
@IMTHEFOOL ye dekh skte ho
acha mein along the incline le lia a1
correct toh hai na?
a1 assume kar sakte hain kya? Ki in which direction you would want to take? Dono me same ans aayega?
Yup
good ques
Sahi ayega its just mene usko downward lia
Mujhe wall ka normal include nhi krna tha islie
mera a1 is relaitve to incline?
parallel mana na tumne surface ke
surface in contact yes
yup fir theek hai
Mera bhi doubt tha
Check kar lena aaplog pls🙏🏻
..
nsintheta
Oh sorri
Nsintheta is m2a2
m2g ke equal kese hoga ground ka bhi to kuch normal ayega na m2 pr
oh han tbhi gadbad hui
Yup
Krdu close?
@CorrodedCoffin
yeah
+solved @CorrodedCoffin
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