37 replies

Confusion Between `Effect.fn`, `Effect.fnUntraced`, and `Effect.fn("SpanName")`

I'm super confused between the difference of

Effect.fn(function*() {...})

Effect.fn(function*() {...})

Effect.fnUntraced(function*() {...})

Effect.fnUntraced(function*() {...})

and

Effect.fn("SpanName")(function*() {...})

Effect.fn("SpanName")(function*() {...})

baz

baz

(fnUntraced) correctly shows logWarning,

bar

bar

(just fn) kills the program, shows stacktrace on the parent span, but DOESNT EVEN LOG THE WARNING??

And

foo

foo

(Effect.fn("SpanName")) works as expected.

This is quite weird. I expected

Effect.fn(function*() {})

Effect.fn(function*() {})

to work just the same as

fnUntraced

fnUntraced

, except with automatic tracing span, but this playground shows that

Effect.fn

Effect.fn

actually swallows logs?