pnc
i was thinking f(a) can be 2,3,4 (3 options)
now from b c d e , any 3 elements are to be chosen to fulfil the onto condition and then the remaining letter can take any value
so the ans will become
3 * 4c3 * 3! * 4 = 288 but thats wrong
now from b c d e , any 3 elements are to be chosen to fulfil the onto condition and then the remaining letter can take any value
so the ans will become
3 * 4c3 * 3! * 4 = 288 but thats wrong
