8 replies

wrapping a generic function in typescript

i'm trying to write a wrapper to automatically handle loading state when necessary. my idea is to wrap my function definitions in this function

busyable

busyable

which then returns a function that precedes and succeeds the callback passed in by toggling busy state. something like this:

    const busyable = (fn: (...args: any) => Promise<void>) => {
        return async (...args: any) => {
            busy = true;
            await fn(...args);
            busy = false;
        };
    };

    const busyable = (fn: (...args: any) => Promise<void>) => {
        return async (...args: any) => {
            busy = true;
            await fn(...args);
            busy = false;
        };
    };

something is off (likely function parameters), and it seems like my function might be getting run twice. any help is appreciated.

TTC

Theo's Typesafe Cult•4y ago•

8 replies

jack

wrapping a generic function in typescript

i'm trying to write a wrapper to automatically handle loading state when necessary. my idea is to wrap my function definitions in this function

busyable

busyable

which then returns a function that precedes and succeeds the callback passed in by toggling busy state. something like this:

    const busyable = (fn: (...args: any) => Promise<void>) => {
        return async (...args: any) => {
            busy = true;
            await fn(...args);
            busy = false;
        };
    };

    const busyable = (fn: (...args: any) => Promise<void>) => {
        return async (...args: any) => {
            busy = true;
            await fn(...args);
            busy = false;
        };
    };

something is off (likely function parameters), and it seems like my function might be getting run twice. any help is appreciated.

wrapping a generic function in typescript

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