Function call in hook with React

So heres is the thing, and i'm trying to study javascript refence x copy, and shallow copy, to understand it. Basically, if we have a function, and put it into a hook, and export it from the hook:
// myHook.ts
const useSuccess = setSuccessOverlay() // this is a hook, now useSuccess has: {openOverlay(), closeOverlay(), isOpen }

export {
useSuccess
}

// firstScreen.tsx

const { useSuccess } = myHook()

<Overlay isOpen={useSuccess.isOpen}>
//code
</Overlay>

// secondScreen.tsx

const { useSuccess } = myHook()

const makeOverlayOpen = () => {
useSuccess.openOverlay()
}

<Button onClick={makeOverlayOpen}>...
// rest of the code
// myHook.ts
const useSuccess = setSuccessOverlay() // this is a hook, now useSuccess has: {openOverlay(), closeOverlay(), isOpen }

export {
useSuccess
}

// firstScreen.tsx

const { useSuccess } = myHook()

<Overlay isOpen={useSuccess.isOpen}>
//code
</Overlay>

// secondScreen.tsx

const { useSuccess } = myHook()

const makeOverlayOpen = () => {
useSuccess.openOverlay()
}

<Button onClick={makeOverlayOpen}>...
// rest of the code
so, when i click on the Button, the overlay of firstScreen doesn't open, like, if a add a navigation on the onclick, and make
const makeOverlayOpen = () => {
nav('firstScreen')
useSuccess.openOverlay()
}
const makeOverlayOpen = () => {
nav('firstScreen')
useSuccess.openOverlay()
}
it will nav to the first screen, and the useSuccess tha comes from the hook, comes with isOpen = false even that, if a add a log on the click:
const makeOverlayOpen = () => {
nav('firstScreen')
useSuccess.openOverlay()
console.debug(useSuccess.isOpen) // returns true
}
const makeOverlayOpen = () => {
nav('firstScreen')
useSuccess.openOverlay()
console.debug(useSuccess.isOpen) // returns true
}
it's like each useSuccess that i reference when calling fron the hook, is a diffrent function in memory, pointers to a different one
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