5 replies

Union of literal types from an array of strings

Hi I'm looking for a way to generate a union type for every string in an array.

Let's say I have an array

const sample = ["apple", "banana", "grape", "orange""]

const sample = ["apple", "banana", "grape", "orange""]

. Basically I want to be able to get

type SomeType = "apple" | "banana" | "grape" | "orange"

type SomeType = "apple" | "banana" | "grape" | "orange"

. I need this

SomeType

SomeType

because I need to create a function that accepts one of these values instead of typing them one by one like this

const aFunction = (text: "apple" | "banana" | "grape" | "orange") => {
  // do something with text
}

const aFunction = (text: "apple" | "banana" | "grape" | "orange") => {
  // do something with text
}

As you can see it'll be a lot of work to do the typing if the number of items in the array keeps increasing (let's say like 100 items). I just want a union type that consists of the literal types of whatever strings that are in the array (in this case

sample

sample

). How can I do this in typescript?

KP-C

Kevin Powell - Community•3y ago•

5 replies

Sinc02

Union of literal types from an array of strings

Hi I'm looking for a way to generate a union type for every string in an array.

Let's say I have an array

const sample = ["apple", "banana", "grape", "orange""]

const sample = ["apple", "banana", "grape", "orange""]

. Basically I want to be able to get

type SomeType = "apple" | "banana" | "grape" | "orange"

type SomeType = "apple" | "banana" | "grape" | "orange"

. I need this

SomeType

SomeType

because I need to create a function that accepts one of these values instead of typing them one by one like this

const aFunction = (text: "apple" | "banana" | "grape" | "orange") => {
  // do something with text
}

const aFunction = (text: "apple" | "banana" | "grape" | "orange") => {
  // do something with text
}

sample

sample

). How can I do this in typescript?

Union of literal types from an array of strings

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