Giovanni S | Flow (2024-04-05)
How computationally expensive is calling
someArray.length - does it require enumeration over the entire array or is it constant time?7 Replies
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If this is a technical question that others may benefit from, considering also asking it on Stackoverflow: https://stackoverflow.com/questions/ask?tags=onflow-cadenceIt's constant time, it's cheap
Is that also the case for dictionaries? I thought there were previously concerns about computation required to get
someMapping.lengthUnknown User•2mo ago
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Amazing, thank you. I'll need to play around with it
No, AFAIK the length is stored in the root. cc @Faye | Flow
Unknown User•2mo ago
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