mole concept (POAC)
Here is what I tried
3X + 5H2 --> XH4 + X2H6
Let molecular weight of X be m g/mol
Applied POAC for x by taking product masses as 5.628 minus x and x
Obtained an equation in x and m
3(5/m) = (x/m+4)+(2)[(5.628-x)/(2m+6)]
15/m = (x/m+4)+(11.256-2x)/(2m+6)
Also given in the question that moles are in the ratio 2:1 for the product
Thus,
2x/m+4 = (5.628-x)/(2m+6)
Solving these 2 equations gives a negative molecular weight for X
3X + 5H2 --> XH4 + X2H6
Let molecular weight of X be m g/mol
Applied POAC for x by taking product masses as 5.628 minus x and x
Obtained an equation in x and m
3(5/m) = (x/m+4)+(2)[(5.628-x)/(2m+6)]
15/m = (x/m+4)+(11.256-2x)/(2m+6)
Also given in the question that moles are in the ratio 2:1 for the product
Thus,
2x/m+4 = (5.628-x)/(2m+6)
Solving these 2 equations gives a negative molecular weight for X
