Isobutyraldehyde Aldol or Cannizzaro?
My teacher told me that isobutyraldehyde can't undergo aldol since its too sterically crowded and is thus an exception, and that it gives Cannizzaro on reaction with a base.
But in a mains '22 question, isobutyraldehyde reacts with formaldehyde to give an aldol product. What's going on here?
But in a mains '22 question, isobutyraldehyde reacts with formaldehyde to give an aldol product. What's going on here?
