24 Replies
@Gyro Gearloose
Note for OP
+solved @user1 @user2... to close the thread when your doubt is solved. Mention the users who helped you solve the doubt. This will be added to their stats.@Nimboi
for V:
in series, potential difference gets split across resistors. since
i is constant, V across a resistor is directly proportional to its i value (V=IR)
so V1 and V2 get split proportionally according to R
do you see how R2 / R1+R2 and R1 / R1+R2 is just ratio splitting?
like if the battery V was 6 ohms, and the 2 resistances were 1 ohm and 5 ohm, then V1 and V2 would be 1V and 5Vcan we derive it by kcl and kvl
its similar for i:
in parallel V is constant, and i = V/R, so i is inversely proportional to R
.
what will that give you bro?
V = iR1 + iR2
i = i1 + i2
this is not an asked derivation, this is a concept
no i was asking how to get to this result ?
i did it 2, 3 months ago
read my previous messages na
now i dont remember it
this
lets say you dont know this formula and you have to find v2 and all the info is given
how will you find it
instead of asking alternate questions, just tell me what doubt you have in the thing i already gave
@Osama Atankwaadi fine i got an alternate explanation
V1 = iR1, V2 = iR2
ohms law
i = V / R1+R2
bas
i substitute kar doya bro
i did it
done
thanks
cool
it was by using kvl
kaise kiya batao
i was actually doing that so was not able to reply
v-iR1-iR2=0
v = (R1+R2)i
ohms law hi hai voh
but yeah
you'll get it
V1=ixR1
i = V1/R1
SUBSTITUTE I
v = (R1+R2)(V1/R1)
V1 = VR1/R1+R2
done
bro
thanks
ha yes yes
I was asking you this
derivation
but ig u didnt got what i was asking for
but np cool thanks
different ways to convey it par ek hi baat hai
hello!
Please check dms.
+solved @Nimboi
Post locked and archived successfully!
Archived by
<@1035556259417571408> (1035556259417571408)
Time
<t:1739202407:R>
Solved by
<@717724055217635398> (717724055217635398)