eas
biphenyl undergoes friedel craft acylation with ch3cocl followed by nitration , give the structure of final product
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@Dexter
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problem lies in nitration
where should nitro go
i say this but key says otherwise
What does key say?
neeche wali ring ke meta pae
Nitro goes on relatively electron rich ring
Carbonyl is stronger withdrawing group than phenyl with a carbonyl group on the para position
Second ring is more electron rich relatively.
during eas we follow the command of weak o/p director over strong meta director tho??
Haan, par phenyl bhi withdrawing hai na?
phenyl is o/p director and activator for sure
Wait
Yeah, it's activating here. Huh
Still, I feel the second rich is gonna have more electron density because the carbonyl group is not directly attached to it.
why is the whole top ring system activating?
It's not activating. It's just less deactivating
i got it guys
meta pe jayega neeche wali ring ke
🗿
That's why meta
its less deactivating compared to what boi
Compared to the acyl on the top benzene
no that's fine, that's why it ends up on the bottom ring
but how do you decide where on the bottom ring it ends up
meta or para
ek ring pe ch3co laga hai which deactivates that very ring , so comparitively the other one is more activated
i got that part
Deactivating group, so meta
ab c=o ke electron o pe transfer karke +ve charge resonate karaoge toh youll notice that o/p par jayega
ignore the red arrows
oh the whole top ring system acts as deactivating because of the acyl
Look at it this way.
1. NO2 aaya. Dekha ki kahaan pe electrons hai. Dusra ring
2. Dusra ring pe kahaan hai electrons? Meta
so meta pe electron density jyada toh wahin jayega
yeah got it
solved mark kardu?
yeap
alr
thanx everyone
+solved @Opt
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