thermal conduction

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45 Replies
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@Gyro Gearloose
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Dexter
Dexter7mo ago
wow interesting I = -KAdt/dx but dt isn't constant I will be dq/dt im not getting the equations
Opt
Opt7mo ago
Yum. I started doing it and got a second order DE Got general solution for one side. Need to solve for other side, input conditions
Dexter
Dexter7mo ago
Im getting three d wale terms dT/dx in the RHS dq/dt in the LHS
Opt
Opt7mo ago
Let me try from the beginning actually
Dexter
Dexter7mo ago
can't find how to relate all these
Opt
Opt7mo ago
Wait you took dT/dx into consideration? The rod has negligible heat capacity so I assumed its temperature can be ignored. Huh Yeah, then I messed up
Dexter
Dexter7mo ago
the source and sink are at different temperatures so the heat flow should be through the rod as well
Opt
Opt7mo ago
Yup tup *yup Crap I did all of this wrong
Dexter
Dexter7mo ago
😭
Opt
Opt7mo ago
Got this and all
No description
Opt
Opt7mo ago
Curve which like charging capacitor in RC circuit for comparison. Which makes sense.
Dexter
Dexter7mo ago
time and temperature ko leke differential format banana hai but idk what to with the dx
Opt
Opt7mo ago
Since it should asymptote
Dexter
Dexter7mo ago
interesting i see
Opt
Opt7mo ago
$Sa$ is $m{a}s_{a}$
TeXit
TeXit7mo ago
Opt
No description
Dexter
Dexter7mo ago
yeah It does it'll attain a steady state when T1 = T2
Opt
Opt7mo ago
Ta = Tb. T1 and T2 are initial values I didn't want to get confused
Dexter
Dexter7mo ago
oh haan yesyes I can't get the equations to work
Opt
Opt7mo ago
Wait, won't that temp be (T1+T2)/2 ?
Dexter
Dexter7mo ago
why so?
Opt
Opt7mo ago
Just checking. Nvm it depends on initial difference
Dexter
Dexter7mo ago
i see
Opt
Opt7mo ago
IT ALL HECKING COLLAPSED PRACTICALLY EVERYTHING CANCELLED Final answer I got was exponential decay $\delta T(t) = (T_2 - T1)e^{-\frac{KA(m{1}s{1}+m{2}s{2})}{m{1}s{1}m{2}s_{2}l}t}$
TeXit
TeXit7mo ago
Opt
No description
Opt
Opt7mo ago
All conditions are satisfied Afaik @hardcoreisdead pls confirm Because I didn't take temp.grad. into consideration @Dexter see if you got the same result
Hithav
Hithav7mo ago
No description
Dexter
Dexter7mo ago
ah ok dT = dQ/ms😞 😞
flower
flower7mo ago
Newton's law of cooling
Dexter
Dexter7mo ago
no Its conduction that was radiation
flower
flower7mo ago
Ohhhhh right
Hithav
Hithav7mo ago
yeah it's not intuitive i had solved a similar ques before so it was all bit easier :sweaty:
Dexter
Dexter7mo ago
idk man im not able to solve good questions aajkal quality has Deteriorated alot
Hithav
Hithav7mo ago
4 more days left after that you will get back your form ,even I don't get new kinds of ques i end up seeing soln after 10-15 mins
Dexter
Dexter7mo ago
idfk if I'll be able to crack good questions anymore man Feeling very demotivated nowadays
Opt
Opt7mo ago
You did the simple thing 🤦‍♂️ I did Ta, Tb individually and subtracted lmao
CorrodedCoffin
CorrodedCoffinOP7mo ago
Exact answer
No description
Opt
Opt7mo ago
Yup, same thing. I just took LCM
CorrodedCoffin
CorrodedCoffinOP7mo ago
Your T2-T1 implies T20-T10 or inverse of that Explain the logic of this ques pls
Opt
Opt7mo ago
There's a mod involved because of the integration
CorrodedCoffin
CorrodedCoffinOP7mo ago
+solved @Opt
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