22 Replies
@Apu
Note for OP
+solved @user1 @user2... to close the thread when your doubt is solved. Mention the users who helped you solve the doubt. This will be added to their stats.36=2^2 3^2
let digits be abcde
abcde =36 = 2^2 3^2
this mein 2 2's and 2 3's are to be distributed among 5 distinct "boxes" beggar coin theorem se 6c4*6c4
where am i going wrong
thats what i was about to say
there will be more cases
not only of 2,3,2
digits can repeat
since it just said natural number
2,2,3,3
4,9
2,2,9
2,3,6
6,6
4,3,3
Am I missing any?
lemme see
nop
Now it's just a matter of ordering and inserting 1's as necessary
Not 0's, mb
It has to be 1's
Like, 41119
Because product has to be 36
that is accounted for in my method
Oh, you have repetition allowed.
think of it as boxes named a b c d e
in these 2 2's are to be distributed and 2 3's
not mentioned?
Yeah i misunderstood your box definition
Ok, one issue is gonna be that you're gonna end up with two digit numbers in each box, which is wrong
2 2's in a means 2*2
not 22 or 2+2
Ok, but you can also have 2,2,3 which is 12 in one box. But one box can only have a single digit number
ohh that explains the overcounting
Yup
then casework is the only soln?
Yeah, it's annoying but yes
😠alr
Right ?
Here my method works bcuz it's not mentioned x is a single digit integer
it is mentioned
it says natural number which can have repeated digits
+solved @Opt
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