Solids/waves, frequency of a bar

A uniform metal rod of length 1m is clamped at two points 5 cm from one end and 15 cm from the other end. The possible frequencies of the natural oscillations (longitudinal) of the rod can be (Y=1.6×1011 N/m2, ρ=2500 kg/m3)
A uniform metal rod of length 1m is clamped at two points 5 cm from one end and 15 cm from the other end. The possible frequencies of the natural oscillations (longitudinal) of the rod can be (Y=1.6×1011 N/m2, ρ=2500 kg/m3)
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18 Replies
iTeachChem Helper
@Gyro Gearloose
iTeachChem Helper
Note for OP
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Nimboi [ping if answering]
i used f = nv/2l, v = sqrt(Y/rho) and got f = 5000n i considered length as 0.8 however, all the options satisfy f = 5000n
Sephrina
Sephrina3w ago
did u try using length as 1m
Nimboi [ping if answering]
and the correct answer is 40kHz, 120kHz gives 4000n and multiple options satisfy that too
Sephrina
Sephrina3w ago
hm weird
Nimboi [ping if answering]
the reason im not posting the options is because mathongo plasters your name and email all over the question so you cant pirate them ill just type them out
Sephrina
Sephrina3w ago
...wow yeah thts better
Nimboi [ping if answering]
10kHz, 50kHz
40kHz, 120kHz (correct)
80kHz, 100kHz
120kHz, 150kHz
60kHz, 100kHz
10kHz, 50kHz
40kHz, 120kHz (correct)
80kHz, 100kHz
120kHz, 150kHz
60kHz, 100kHz
trin
trin3w ago
theres a trick for that, bookmark that question then go to the bookmarked section, it will be completely blue bg
Nimboi [ping if answering]
damn lmao mad thank u
iTeachChem
iTeachChem3w ago
.nice
SirLancelotDuLac
Okay, since there are the 2 free ends, shouldn't they also be anti-nodes? That and the clamped ends should be nodes gives you some extra constraint.
Sephrina
Sephrina3w ago
No description
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Sephrina
Sephrina3w ago
copy pasted google @Nimboi [ping if answering]
Nimboi [ping if answering]
ah yes got this thanks yall +solved SirLancelotDuLac Sephs
iTeachChem Helper
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