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@Gyro Gearloose
Note for OP
+solved @user1 @user2... to close the thread when your doubt is solved. Mention the users who helped you solve the doubt. This will be added to their stats.how do i get path difference
i took angle of incidence of wave to be theta so dist travelled by one waves is (a+x)sectheta
hypotenuse the triangle i have marked in the figure gives dist by the other wave
((a-x)^2+D^2)^1/2
after approximation it becomes D (?)
also D = (a+x) tantheta
so delta = (a+x)(sec-tan)
i dont have more info about sec and tan tho
so how can i proceed
clear image
U can do like this
