Electrostat

To ye semicircular ring h uniform charge density ki and mujhe jo blue pint h uske about nikalni h field. Lets say ki blue point ka altitude given To fir iske upar field kese nikalenge. I thought of integrating the e vectors depicted in red but distance is also changing . Could also look at it like a bended rod
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12 Replies
iTeachChem Helper
@Gyro Gearloose
iTeachChem Helper
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727
7273w ago
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Narrator
NarratorOP3w ago
You can't integrate it like this, the distance between dq and particle is always changing
Opt
Opt3w ago
,rotate
TeXit
TeXit3w ago
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Opt
Opt3w ago
The x component is turning out to be more troublesome
727
7273w ago
oh mb i thought you were talking about the center of ring
Narrator
NarratorOP3w ago
Yeah i tried that, its mind bending to say the least
Opt
Opt3w ago
I'm pretty sure it's going to be an elliptic integral with no elementary antiderivativr
integralofe^2x
okay so as u can see i found the distance x between point of observation and ring and found rest all using vectors and shit for electric field its js integration from 0 to pi of kdQ/x^2 and write dQ as lambda r * d(theta) (assuming like negligible thickness no surface area charge density and shit) and find out to components by doing sin(phi) for vertical (y component) and cos(phi) for horizontal ( x component) (i used some trig indentities to simplify phi) OH and also imp thing try putting in h=0 for a suprise
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integralofe^2x
and those integrals are non solvable btw in this form only solvable for cases like h=0 or h>>R or h=R i think not sure u can check btw this can be wrong too so ya

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