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@Gyro Gearloose
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Nvm my solution is wrong
bhiya ye kya hai
mera to sar ghum gya
Ye to mains level ka hai-
NEET level
1.Summation Tivi=0 se 3T(3)+2T*2-T.v(P)=0 or velocity=13m/s.
2. (velocity at Q+velocity at P)/2=3, so 13+v=6 or velocity at Q is 7.
3. Similar to 2, gives velocity as 3m/s,
4. velocity of pulley B=velocity of block=2m/s
Can u explain the usage of TiVi=0
We take tensions on blocks and point P but not consider T.Vq and T.Vr into eqn
Assume there is some block on the open end of the string which is being pulled with some velocity, then do summation TiVi=0
just a follow-up doubt.. the application of t.v will include the pulleys if we dont consider them to be massless right
bro can we just aply this for like
any select points/pulleys we choose??
also 2 me kaise likha aapne?
No use only and everywhere where string is open so as to speak.
2 wala if you know the formula v_p=(v1+v2)/2 or you can visualize that if in 1 second pulley moves v_p to the left, 2v_p string passes from bottom to top, so their relative Velocity must be 2v_p
ahh makes sense
ahh ok
but then why dont we in Vq and Vr
We add TiVi wherever there is an open end to the string. (Apart from where it is connected to pulleys)
oh
got it
.
Doubt
In first part 3T(3)+2T(2) ki jagah 3T(3)-2T(2) nhi hona chahiye?
2T and v=2m/s are in the same direction, so it would be 2T*2.
Got it bro imma close this out
Thanks
+solved @SirLancelotDuLac
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