Kinetics
how do i find R in terms of Rt
R = rotaion
At a time t = rotation of Sucrose = R0 - R
i cant find R in terms of Rt as we do in pressure rate law

28 Replies
@Dexter
Note for OP
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ye idc whats the worst someone gonna do
call me?
W opinion
.noted
delete it bro
I got 104.233424
With a calculator
(30ln(45/11))/ln(1.5)
am asking how we get r in terms of Rt
like we used to do in pressure
Ok, set initial conc. of sucrose to be 1.
Let specific rotation of sucrose, glucose, and fructose be a,b,c respectively.
Rotation = a[sucrose]+b[glucose]+c[fructose]
c is actually going to be negative but that doesn't change anything.
And since [glucose]=[fructose],
You can write
θ= (a)(1-x)+(b+c)(x)
You get value of a from initial data.
You get value of b+c from the end point data
And then it's a matter of substituting and calculating
Using first order kinetics because water is in excess
ok what about after calculating abc
Write down the concentrations at various times. From the data for 19°, you get the value of k.
From that you can calculate value of x such that θ=0
And from there you get t
no like
we do
Wait lemme write it down and send
kt = ln (R0/R0-R)
Yeah
how do we get R in terms of R0 and Rt
It's not R0-R tho? It's R0/R
Initial/left
what
it was R0 Rotaion
then R rotaion went out and became product or smth
like we do in moles and pressure
we cant do here?
Oh rotation
I just calculated concentration
It's easier
Well, moles
I just calculated moles
Because rotation = specific rotation × concentration, but since volume is fixed, we can take it as specific rotation×no.of moles
ooh
so we can do the whole thing in mole
ic
ic
who knows bhai call karke galiyana shuru kar de

i got this from calculator
but how the hell are we suppose to find ln(45/11)??
Yeah same
God knows.
ok thx for the concept
+solved @Opt
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