PnC
How to do the 4th option
i tried doing it the normal way for least and then subtrating the cases where G1 and M1 are together i dont get ans
2B 2G = 120
3G 1B = 50
4G 0B = 5
these are my final ans including if G1 and M1 are not together
17 Replies
@Apu
Note for OP
+solved @user1 @user2... to close the thread when your doubt is solved. Mention the users who helped you solve the doubt. This will be added to their stats.My approach lemme calc that out real quick
Ahh I'm getting 195
its also not in the option lol
Yeà
Thnng is
Maine baaki 3 ka final answer tak nikalla hai pele
But 4 ka nahi nikala tha
Idk why
Aur ab nikal ni ra
This is case-working ig.
The only part of pnc I dislike.🥴
But yeah, make cases for there being 2 girls, 3 girls and 4 girls
And in each case account for if M1 and G1 are chosen
Which would give 189 ig
k G means "k girls are chosen"
ye ik this will work
but what is wrong with my apporach
For the first case there would be 150-20=130 cases feasible
For the second one there would be 10*6-6=54 cases feasible
why?
Consider 6C25C2 the number of ways for chossing members now let one of 'em be G1 and one be B1 then number of ways to choose remaining are 4C1*5C1
omg i did that and calculated that as 30 i am beyond cooked 💀
in the 2nd one
wont it be 10x6 -10
why 6?
5c2
= 10
We are taking 3 girls and have already chosen the one boy (B1), so we only need to choose 2 girls, that can be done in 4C2=6 ways in the second case
oh fuk ye right 4c2
i get it now
+solved @SirLancelotDuLac
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