18 Replies
@Gyro Gearloose
Note for OP
+solved @user1 @user2... to close the thread when your doubt is solved. Mention the users who helped you solve the doubt. This will be added to their stats.I'm getting 420.44
With a calculator
The answer is (2)^1/4 x 500 which is approx 600K
The ans has been obtained from this eqn
? I got 500 divided by 2^¼
*1/4
Not multiplied
ohhh
500²-T⁴ = T⁴-0⁴
I don't understand why they've taken it twice
In the LHS of this eqn, the first term is heat given by spaceship and the second term is heat given by black screen
Ok, are they assuming that radiation takes place back to only the space station?
but idk how temperature of black screen is 500K?
I think they have assumed spaceship and black screen as surroundings and the black shell as the body
and since they are asking for temp in steady state, rate of emission is equal to rate of absorption
@SirLancelotDuLac @Gamertug any idea?
my everything except mechanics and electric thing is weak , no idea
oh okay np
No clue, I'm getting 500/2^0.25.
Right?
ohh okay
