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@Gyro Gearloose
Note for OP
+solved @user1 @user2... to close the thread when your doubt is solved. Mention the users who helped you solve the doubt. This will be added to their stats.wait didnt it say the chnge is equal in both ac and cb
Assuming AC = x and BC = l, I did $\Delta l{AB} = \frac{mgl}{2AY}$ and $\Delta l{AC} = \frac{mgx \cdot x}{lAY} \newline$
Equating both I got $\frac{x}{l} = \frac{1}{\sqrt(2)}$
Nimboi [ping if answering]
did u learn how to write these lol
also lemme try
i just picked up on it through opt and lancelot and screwed around in my private server a little
also i have a one page cheatsheet pdf for LateX
why did u do Ab / AC
wait
whats the use of AB
the change in length of AB (full wire) = the change in length of AC right
AB is the full wire
wait
no
💀
OH
lmao
change in length of BC is not the same as that of whole wire
this is trippy af
wait
what
wait nvm
nah its not trippy
ill try again
its just brainfart moment
@Gamertug wait whats the expression for change in length of BC?
for BC it will only take BC weight
for AC it will take whole wire weight at the end , like AC and BC at the end
wait da i think i need to integrate
force varies along the length
wallah
got it
im only used to direct formula application in this chapter
nice question
+solved @Gamertug
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