Probability
for the thing we have to find we can do P(intersection of 3)/P(intersection of White and Green)
since it wants white in first and green in second i did
1/3 x 1/6
but i did not get ans
18 Replies
@Apu
Note for OP
+solved @user1 @user2... to close the thread when your doubt is solved. Mention the users who helped you solve the doubt. This will be added to their stats.how did you do 1/3 and 1/6 arent there N balls so shouldnt you do 3/Nand 6/N-1
Well, it seems they have given more information than necessary to me :/
But from the last line, if there are n balls initially then there are n-9 blue balls. Since the first and second draws were white and green, the probability that from remaining balls, the ball drawn is blue is n-9/n-2=2/9 from here n=11
You can put the value of n=11 in the second condition to see this is true.
(Note that the color of the drawn balls are independant probabilities, or am I tripping somewhere?)
why?
out of the 3 white balls
i selected 1
and out of the 6 green
i selected 1
ans is indeed 11
what how did u do that last part
It is given to us that the first ball drawn is white and the second one is green, the probability that the third ball is blue is (no. of balls that are blue)/(no. of remaining balls); the number of balls that are blue in color are n-9 while the number of remaining balls are n-2
Oh wait that sounds weird. :psyduck:
oooh i got it
this was in the solution , what did i do wrong? the 3/n and 6/N-1 was in the solution too
selecting 1/3 , 1 from 3 whites whts wrong with this
We want the probability that a white ball is chosen from all the other balls (which are n in number) so the probability for the same is 3/n
isnt that the same as saying i chose 1 white ball from the 3 white balls?
they are basically the same we chose 1 ball from white only
From the first line, (2/5N)(9/2)=P(intersection of white and green)=3.6/(n-1).n which would give the same result i guess.
No, because the first ball can be possibly green and blue also, W_1 denotes the event that the first ball drawn is white and not that one ball is drawn from white
the first ball drawn is white
so the first ball is 1/3
idk whats wrong with this
3/N also makes sense
But it could have been blue or green also right?
yes ,but we arnt even taking that in considration
it says first ball drawn is white
oooh
wait
ic
That is the desired outcome. The total outcomes need to have green and blue.
u are talking about the whole prob
ye
makes sense
@iTeachChem @CertifiedBrownMunda
or will it include another
k-1
im not so sure
I am sorry but I couldnt read the calculation part
This is a fair analysis