Electric Flux
Why electric flux due to charge outside the gaussian surface is zero.
i know 2 explanations,
1. Qinside/ε₀ = 0 as there isn't any charge inside the gaussian surface.
2. Jitni Field lines enter kar rahi hain, utni hi exit kar rahi so flux total = 0
But can someone please explain if we try integrating E.dA vector, we get 0 for charge outside.
integrate karke zero kaise aaega?
11 Replies
@Gyro Gearloose
Note for OP
+solved @user1 @user2... to close the thread when your doubt is solved. Mention the users who helped you solve the doubt. This will be added to their stats.apke ik var integrate karne ka try kiya?
sorry i didn't get it!
matlab aap kya kehna chah rahe ho mujhe samaj nahin aaya
You'd need to look up a proof of the Gauss Divergence Theorem
If you're fine with vector calculus, I can share one
yes sir please
Khan Academy
YouTube
Divergence theorem proof (part 1) | Divergence theorem | Multivaria...
Courses on Khan Academy are always 100% free. Start practicing—and saving your progress—now: https://www.khanacademy.org/math/multivariable-calculus/greens-theorem-and-stokes-theorem/divergence-theorem-proof/v/divergence-theorem-proof-part-1
Setting up the proof for the divergence theorem
Watch the next lesson: https://www.khanacademy.org...
There's multiple parts
This is gonna be overkill though
You can also find it here.
https://www.feynmanlectures.caltech.edu/II_03.html
thank you so much brother!
all the best!
have a nice day!
+solved @Opt
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i was saying thtt did u try to integrate it by yourself once?