28 Replies
@Apu
Note for OP
+solved @user1 @user2... to close the thread when your doubt is solved. Mention the users who helped you solve the doubt. This will be added to their stats.Try to remove one of the f(x)
Just use complex numbers
Oops sry didn't mean to ping u
@hardcoreisdead
That is not proper tho thats a assumption
Isn't it a method for solving it?
Its nice
Nvm
Standard method
Idk
I use thie
Just doesnt apply to all functions satisfying it
It only applies for linear relations
Btw
we good?
Yea
:/
totally forgot this
what is t and how is f(x)=1
what substitution is done
It's a shortcut trick my teacher taught
oh can u explain a bit about it
u just replace f(x+t) with x^t and solve. Then find out the lowest common number to make both the solutions phase diff to be 2pi and that's ur period
Try it out for another problem and check it out
Close this ig
hm whyd we take f(x+t) as x^t
wahi merko bhi ni samjha
traditional method is gadha majdoori
real i just saw a random solution online
its like newton sum
a question similar to this one.
Soln by SirLanceALotDuLac
this has the proof of the complex number method
Instead of plugging in Tn, Tn-1 and Tn-2 into a quadratic you basically reverse engineer. You have f(x),f(x-1),f(x+1) [Tn, Tn-1 and Tn-2 in this case] and form a quadratic
The proof is pretty similar to newton's sum method
damn
crazy
love it
@hardcoreisdead did you understand?
+solved @Fusion
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