29 Replies
@Gyro Gearloose
Note for OP
+solved @user1 @user2... to close the thread when your doubt is solved. Mention the users who helped you solve the doubt. This will be added to their stats.divide by 2 in the numerator and denominator, with the intention of clubbing the
sin and cos terms into oneayien ye kya hai
you'll get $\frac{1}{2}sin(x) + \frac{\sqrt{3}}{2}cos(x) = cos(\frac{\pi}{6} - x)$ in the denominator
Nimboi
ahhh, ic
then you can differentiate
for minimum val
minima
ok
got it
@Nimboi one more
im getting 1/4 here
option mein ni h
ohh wait
yeh ulta poocha hai
got it
alternatively, the maximum and minimum value of $asin(x) + bcos(x)$ are $\pm \sqrt{a^2 + b^2}$ so you can just do that from the first step
Nimboi
since the trig expression is in the denom
when its maximum,
y will be minimum
simpler method1/2 waale se ban gya woh
answer 5 aaya
yep
i think its actually
-5 technically
but ehdone
thanks
options galat hai
-5 hoga not 5
actually we're all wrong and it should be minus infinity
oh right that makes more sense
for whatever reason they only took y positive
physics mein padha rhe h
maybe thats why
btw thanks
aise nhi hota 💀 but np
+solved @Nimboi
math is math
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