Mathematics limits
So I came accross a question of limits
y = [2x³-1], xε[1,2).
Find the number of points of discontinuity of this function. And I can't understand why 1 is not included in discontinuity.??
18 Replies
@Apu
Note for OP
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since the interval is [1,2) we can only check for RHL at x=1
if RHL at x=1 exists then we can say that function is continous at x = 1
I mean since it's greatest integer function and 1 is included in the range so technically shouldn't it be discontinuous at 1 ?
like yeah, im talking in general
if you want to discuss about continuity at end points
Nah is it correct or not idk
wdym
like [a,b]
then you can only check for RHL for a and LHL for B
if limit exists at end points then function is continous at end points
I am saying that the ans is 13 and not 14
even if we include 1
yeah cuz at 1 the limits exists
how
cuz we will only check for RHL
1+
we cant check for 1-
cuz 1- is not in the given domain
.
but for continuity lhl ,rhl and f(a) should be equal aint it.
we will not check for lhl? for 1
yes this is true for all points in the given interval, but for end points you can only check for LHL / RHL not both
nope
cuz its not in the given domain
or not in the given interval
so by rhl it will be enough?
yes
but this is true only for end points
ohh noted 👍
arigato gozaimas
+solved @Aetherfly
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