field using dipole

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34 Replies
CorrodedCoffin
CorrodedCoffinOP4mo ago
can some1 tell me how to get the answer with and without using dipole
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CorrodedCoffin
CorrodedCoffinOP4mo ago
i tried without dipole and using my imagination i was able to figure out net field should be 4*field due to one charge * sinalpha (alpha mentioned in fig)
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Sephrina
Sephrina4mo ago
take out the feild from each charge and get a vector sum it should give the ans
CorrodedCoffin
CorrodedCoffinOP4mo ago
i got pretty much the same ans but was missing 1/root2 it indeed will but that vector sum itself is bothersome
Sephrina
Sephrina4mo ago
nah it wont be dipole here will make things more complicated
Opt
Opt4mo ago
$$\frac{pK}{\sqrt{2}x^3}\left(\hat{z}-\hat{y}+\hat{z}+\hat{y}\right)$$
TeXit
TeXit4mo ago
Opt
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Opt
Opt4mo ago
That's what I got. Try simplifying, i might have made a mistake
CorrodedCoffin
CorrodedCoffinOP4mo ago
yep this is correct how did u get this
Opt
Opt4mo ago
It's along equatorial plane of both dipoles na?
CorrodedCoffin
CorrodedCoffinOP4mo ago
i couldnt visualise using dipole
Opt
Opt4mo ago
$$-\frac{\vec{p}K}{r^3}$$
TeXit
TeXit4mo ago
Opt
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Opt
Opt4mo ago
Diagonals are also dipoles Use those
CorrodedCoffin
CorrodedCoffinOP4mo ago
yeah i got that part there will be two components of field due to dipole
Opt
Opt4mo ago
Yeah, the two fields are along z-y, and z+y (divided by √2 to make them unit vectors) The p vectors are opposite to those vectors I just wrote. I flipped them in my head and typed it.
CorrodedCoffin
CorrodedCoffinOP4mo ago
how did u fig out the dirn part
Opt
Opt4mo ago
+q to -q For field that is. Dipole moment is always - to +
CorrodedCoffin
CorrodedCoffinOP4mo ago
the dipole in red gives z-y or z+y
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Opt
Opt4mo ago
z-y
CorrodedCoffin
CorrodedCoffinOP4mo ago
i am thinking x+z
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CorrodedCoffin
CorrodedCoffinOP4mo ago
x-z
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CorrodedCoffin
CorrodedCoffinOP4mo ago
wait a min angle between p vector and r vector is 90 so radial component cancels only the other one remains
Opt
Opt4mo ago
Look at the axes They've given the axes already @hardcoreisdead got it?
CorrodedCoffin
CorrodedCoffinOP4mo ago
no not really
Opt
Opt4mo ago
They have effects along axis perpendicular to them as well
iTeachChem
iTeachChem4mo ago
wont that get cancelled out here?
Opt
Opt4mo ago
Oh you mean the field along perpendicular Those don't exist Mb mb Yeah field is always parallel/antiparallel to dipole moment
iTeachChem
iTeachChem4mo ago
haan matlab they are planar, is what i recall
CorrodedCoffin
CorrodedCoffinOP4mo ago
for the marked dipole i am imagining a plane similar to xy plane but tilted 45 degs from y axis inwards
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CorrodedCoffin
CorrodedCoffinOP4mo ago
now angle between p vector and r vector ( from centere of dipole i.e origin to point M) is 0 so field along r vector becomes zero field perpendicualr to r vector is kp/r^3 right ?

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