doubt regarding Hofmann exhaustive elimination product
after rxn with CH3-I what are the factors for formation of the Hoffmann product?
for eg i know the hydrogen at beta position is eliminated, and the carbon with the lowest degree is chosen for elimination. in case of 2 same degree carbons, how is elimination decided? eg question :
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@Dexter
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found this on chem libre texts
most acidic H is removed
reason?
didnt find this anywhere. even in skm sirs lec, he said check degree and alkene stability
Ag2o ko jab moist karte hai toh it turns into agoh
Here, this acts as a base and acid base reaction occurs. So most acidic H is removed
we good? shall we close this out?
i am still not sure. in the first example of this, the lesser acidic H is removed and also hoffman product is minor, it doesnt make sense