Trigonometric inequality
someone said I should try jensen but even then I'm not getting the result
12 Replies
@Apu
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It's not given tho that A,B and C sum upto pi.
Acha yeah I didn’t see
I think it would go something like this.
Iirc this also can be done graphically
Considering the graph of sinx from 0 to π/2
That leads to getting sin((a+b+c)/3) rather than the required sin(a+b+c) ig.
Shouldnt it be -2sin(-(α+β)/2)cos((α+β)/2 + γ) , like -ve inside the sin 2nd term in 2nd line? after applying sinc - sind i mean, cuz if you take it out, then there'll be a +ve sign on the front, right?
yea exactly what i got from jensen's inequality
Yep, I directly took out the - sign and turned it +ve.
my bad i confused myself
after applying cosc-cosd, the argument inside sin is c+d/2 and c-d/2 so shouldnt the arguments be α+γ/2 and β+γ/2 finally? i dont see them divided by 2 in the arguments of sin, maybe i am missing something again lol
@SirLancelotDuLac ...
Oh right mb, they should be divided by 2.