electrostats

is this qn correct?
29 Replies
iTeachChem Helper
@Gyro Gearloose
iTeachChem Helper
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Opt
Opt2w ago
Where's the question?
Aetherfly
AetherflyOP2w ago
ek thin conducting shelll hai radius r charge -q two point charges placed at A and B A is at r1 from centre r1 < r and B is at 2r from centre in same line A is q and B is 2q if shell is earth then find charge going to eartj
No description
Aetherfly
AetherflyOP2w ago
how do you calculate q after earthing on sphere?
Dexter
Dexter2w ago
Potential of sphere = 0
Aetherfly
AetherflyOP2w ago
how do you calculate that?
Dexter
Dexter2w ago
Sphere ka own potential KQ/r Potential due to inside q = Kq/r1 Potential due to 2q = k(2q)/r2 Summation should be zero Q ki value in terms of q will be obtained Then calculate difference Final - initial
Aetherfly
AetherflyOP2w ago
wait how are you saying that potential due to inside q is Kq/r1
Dexter
Dexter2w ago
Oh wow Yeah actually Lemme see Centre ka potential hota hai na Hollow sphere ka I guess Hollow sphere mein centre ka potential = sphere ka potential
Aetherfly
AetherflyOP2w ago
thats true agar wo q charge andar nahi hota toh
Dexter
Dexter2w ago
Kyun?
Aetherfly
AetherflyOP2w ago
cuz then field inside wouldve been zero
Dexter
Dexter2w ago
Hmm
Aetherfly
AetherflyOP2w ago
so potential at centre = potential of pshere
Dexter
Dexter2w ago
Sochne wali baat hai Let others see this then
SirLancelotDuLac
Potential due to the outside sphere is k(2q)/(2r) and due to inside one is kq/r so the charge on sphere would be -2q for potential to be zero. Also it would be kq/r due to inside charge 'cuz Electromagnetic shielding and sigma*r=constt.
Aetherfly
AetherflyOP2w ago
you mean kq/r1?
SirLancelotDuLac
Nope it would be r.
Aetherfly
AetherflyOP2w ago
potential due to outer charge is K2q/2r on the centr
SirLancelotDuLac
Can I send a voice note if you don't mind?
Aetherfly
AetherflyOP2w ago
yeah sure
Cakey Bot
Cakey Bot2w ago
sirlancelot013
The audio file is too short to be transcribed.
Aetherfly
AetherflyOP2w ago
wait what
SirLancelotDuLac
Oh mb. The charge density won't be constant due to the outside charge, but the potential point still stands ig.
Aetherfly
AetherflyOP2w ago
so KQ/R is potential due to +Q on the sphere, I dont get this part
SirLancelotDuLac
Consider the field lines emanating from +q charge. Now, these field lines enter perpendicularly to the sphere correct? And now, if you look at where the seem to be emanating from, that point would be the center. Hence the kq/r term.
Aetherfly
AetherflyOP2w ago
this is something new sorry for being late

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