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@Gyro Gearloose
Note for OP
+solved @user1 @user2...
to close the thread when your doubt is solved. Mention the users who helped you solve the doubt. This will be added to their stats.Where's the question?
ek thin conducting shelll hai radius r charge -q two point charges placed at A and B A is at r1 from centre r1 < r and B is at 2r from centre in same line A is q and B is 2q
if shell is earth then find charge going to eartj

how do you calculate q after earthing on sphere?
Potential of sphere = 0
how do you calculate that?
Sphere ka own potential KQ/r
Potential due to inside q = Kq/r1
Potential due to 2q = k(2q)/r2
Summation should be zero
Q ki value in terms of q will be obtained
Then calculate difference
Final - initial
wait how are you saying that potential due to inside q is Kq/r1
Oh wow
Yeah actually
Lemme see
Centre ka potential hota hai na
Hollow sphere ka
I guess
Hollow sphere mein centre ka potential = sphere ka potential
thats true agar wo q charge andar nahi hota toh
Kyun?
cuz then field inside wouldve been zero
Hmm
so potential at centre = potential of pshere
Sochne wali baat hai
Let others see this then
Potential due to the outside sphere is k(2q)/(2r) and due to inside one is kq/r so the charge on sphere would be -2q for potential to be zero.
Also it would be kq/r due to inside charge 'cuz Electromagnetic shielding and sigma*r=constt.
you mean kq/r1?
Nope it would be r.
potential due to outer charge is K2q/2r
on the centr
Can I send a voice note if you don't mind?
yeah sure
sirlancelot013
The audio file is too short to be transcribed.
wait what
Oh mb. The charge density won't be constant due to the outside charge, but the potential point still stands ig.
so KQ/R is potential due to +Q on the sphere, I dont get this part
Consider the field lines emanating from +q charge. Now, these field lines enter perpendicularly to the sphere correct?
And now, if you look at where the seem to be emanating from, that point would be the center.
Hence the kq/r term.
this is something new
sorry for being late