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@Apu
Note for OP
+solved @user1 @user2... to close the thread when your doubt is solved. Mention the users who helped you solve the doubt. This will be added to their stats.Have you not done the trigonometry chapters yet?
just entered 11th grade so idk
Notice the graph
As you increase "x"
y also increases
And slope is "change in y" divided by "change in x"
Which turns out to be positive here as you can predict from the observation I mentioned above
In a similar way, you can think of this one as well
Is that fine? @Fie
oh wait wdym by increase in x
oh ok i understand but slopes extend on both sides right
You go from left to right on the graph
(Along x axis basically)
Then notice that y increases each time you go from left to right when theta is less than 90 degree
so when u do that the y factor also increases as it is a slope right?
Slope could be both upward and downward
Think of a hill
oh yea
When you trek upwards
It's an "upward" slope
yea
When you trek downwards
It's a downward slope
yea
Basically how slope is defined is y2-y1 divided by x2-x1
tan theta
Yeah that too
But you said you haven't studied trigonometry yet
ik it from 10th
So I thought of not involving that at all
Yeah alright but it could be explained the other way too so I thought it would be better:)
You got it or should I elaborate a bit more?
it would be nice if u do that
See
yea
As you go from left to right and from down to up
Values of "x" and "y" increase respectively
Right?
yea
now let's focus on x
And let the y change by itself
oh ok
'cause graph is fixed right?
yea
now when we have x2>x1
yea
x2-x1 is positive
Right?
ok
yea
And if you notice
For x2>x1, the graph with theta less than 90 degrees also has y2>y1
'cause it goes upward
Right?
yea acute angle
So y2-y1 is also positive
Both of them are positive
Divide them
What do you get
Positive
yes
Similarly for the obtuse case
When x2>x1, y2<y1
Can you notice that?
yea one negative number
Yeah so one of them is negative
Hence their division gives negative
+/-
ohhh
I guess that's clear now
yea fr thx
Not a problem buddy:)
You gotta speed up though
Even if you're in 11th, this is something very basic
oh yea ur right
Yeah it's something worth explaining
But you gotta do stuff at a better pace
yea
Alright then mark this solved I guess
yea thx
can i friend u maybe
Anytime
Hmm that's alright
my salute goes to u for solving my doubt
bye for now
Damn bhai itna kuch nahi tha dw 😅
B-bye
+solved @Varun_Arora
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