potential and field

A is def correct B. E due to induced charges + E due to dipole = 0 so Einduce = -Edipole = given term C. potential due to induced charges = 0 , potential due to charge on sphere = kQ/R , potental due to dipole = kp/(2r)^2 so net potential at C = kQ/R + kp/4R^2 D. ik Vnet at D = Vind + Vdipole + Vsphere = kp/R^2+ kQ/R + Vind
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83 Replies
iTeachChem Helper
iTeachChem Helperβ€’4d ago
@Gyro Gearloose
iTeachChem Helper
iTeachChem Helperβ€’4d ago
Note for OP
+solved @user1 @user2... to close the thread when your doubt is solved. Mention the users who helped you solve the doubt. This will be added to their stats.
SirLancelotDuLac
SirLancelotDuLacβ€’4d ago
What seems to be the doubt?
hardcoreisdead
hardcoreisdeadOPβ€’4d ago
basically every part except A i dont have the ans key so need to be sure
SirLancelotDuLac
SirLancelotDuLacβ€’4d ago
Also is this from ayjr of this year 😭
hardcoreisdead
hardcoreisdeadOPβ€’4d ago
idk ...
SirLancelotDuLac
SirLancelotDuLacβ€’4d ago
Your reasoning for B seems correct. As for C, the potential inside the sphere will be kQ/R only (because of electromagnetic shielding). As for D, the induced charges will have a tendency to keep the potential the same throughout the sphere, we know that the potential at the center is kq/r and that due to dipole is kp/r^2, so V_ind+V_dipole+kq/r=kq/r, which means D is incorrect ig.
hardcoreisdead
hardcoreisdeadOPβ€’4d ago
This article shows a conducting sphere of charge qo. An external charge q is placed distance x from centre with O as centre and A as a point just inside sphere Is this discussion invalid (In context of option c)
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hardcoreisdead
hardcoreisdeadOPβ€’4d ago
if i clear out Vc i can just do Vd= Vc = Vind + Vdipole + Vsphere = kp/R^2+ kQ/R + Vind to get V due to induced charges on sphere at point D
Augustine
Augustineβ€’4d ago
wont we just add the potential due dipole + potential due to Q charge across the conducting sphere at C since well the sphere is conducting
hardcoreisdead
hardcoreisdeadOPβ€’4d ago
yeah i think the same Vc = kQ/R + kp/4R^2 electrostatic shielding tell us about the electric field at C iirc. at C electric field will be only due to charge induced on inner portion of conductor
Augustine
Augustineβ€’4d ago
yeah potential remains same as the charges just rearrange electric field at c gonna be 0 so Edipole = Echarges on sphere
hardcoreisdead
hardcoreisdeadOPβ€’4d ago
true so A and B are 100% correct
Augustine
Augustineβ€’3d ago
yepp and D too since we did Vc - V (due to dipole at D)
hardcoreisdead
hardcoreisdeadOPβ€’3d ago
but Vc hi toh confirm nahi ho rha
Augustine
Augustineβ€’3d ago
ye hai
SirLancelotDuLac
SirLancelotDuLacβ€’3d ago
But the field inside a hollow sphere is zero, no? Hence the potential remains constant? *This. The field inside the conductor is zero, so you can view it as only the charge on the outer surface of shell has rearranged, while outside charge doesn't influence C, ig.
Augustine
Augustineβ€’3d ago
yes so potential on surface is same as potential at centre before the dipole it was KQ/R but after the dipole is placed, it becomes KQ/R + KQ/4R^2
SirLancelotDuLac
SirLancelotDuLacβ€’3d ago
But the inside of the sphere is not affected by the outside stuff though right? Or am I tripping? 'Cuz of electromagnetic shielding and stuff?
Augustine
Augustineβ€’3d ago
i think that just means that charge rearranges to ensure there is no net electric field inside but potential does change also like logically all charges are still at R dist so potential due to Q charge on sphere is still KQ/R since potential is algebraically added...and potential due to dipole simple gets added since it's positive
ns
nsβ€’3d ago
This is for electric field right.. the shielding part. You can say that for electric field and change in potential, the outer charges won't influence the situation going on inside the shell. But potential at a point will be influenced by it. A,B and D are correct ig.
hardcoreisdead
hardcoreisdeadOPβ€’3d ago
Electrostatic shielding discusses electric field and not potential Remember , if E = 0 then V may or may not be zero but dV= 0
SirLancelotDuLac
SirLancelotDuLacβ€’3d ago
Yeah, I'm confused too. 😭 Do ping me if you find the answer.
hardcoreisdead
hardcoreisdeadOPβ€’3d ago
Alr lol
hardcoreisdead
hardcoreisdeadOPβ€’3d ago
Finally it's ABD
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hardcoreisdead
hardcoreisdeadOPβ€’3d ago
@SirLancelotDuLac
SirLancelotDuLac
SirLancelotDuLacβ€’3d ago
Ah, I see. Lol 1-2 weeks after jee, and I'm already forgetting this stuff.
hardcoreisdead
hardcoreisdeadOPβ€’3d ago
lolol how much u scorin in adv btw
SirLancelotDuLac
SirLancelotDuLacβ€’3d ago
Not well πŸ’€
hardcoreisdead
hardcoreisdeadOPβ€’3d ago
come on cant be that bad
SirLancelotDuLac
SirLancelotDuLacβ€’3d ago
It is ;_; Expecting ~10k this time.
Opt
Optβ€’3d ago
So true.
hardcoreisdead
hardcoreisdeadOPβ€’3d ago
wdym this time u taking drop?
SirLancelotDuLac
SirLancelotDuLacβ€’3d ago
On the fence about it.
hardcoreisdead
hardcoreisdeadOPβ€’3d ago
no no no no
SirLancelotDuLac
SirLancelotDuLacβ€’3d ago
On one hand can't do this stuff for 1 more year 😭
hardcoreisdead
hardcoreisdeadOPβ€’3d ago
πŸ™ kyu mera comp badha rhe lolol
SirLancelotDuLac
SirLancelotDuLacβ€’3d ago
on the other well yk.
hardcoreisdead
hardcoreisdeadOPβ€’3d ago
u r probably getting iiith cse man 99.9 %ile aint no joke
SirLancelotDuLac
SirLancelotDuLacβ€’3d ago
Lmao no man, I'm way behind the competition πŸ˜† Prolly not seeing previous year cutoffs but...sighs in general candidate
hardcoreisdead
hardcoreisdeadOPβ€’3d ago
modest whaa-- 99.9 pe bhi iiith nahi milta ??
SirLancelotDuLac
SirLancelotDuLacβ€’3d ago
If you want cse, probably not. ece mein there is a chance.
hardcoreisdead
hardcoreisdeadOPβ€’3d ago
oh damn nit trichy warangal and stuff ?
Opt
Optβ€’3d ago
Then there's me who's getting nothing Except BITS maybe Good chance with BITS
SirLancelotDuLac
SirLancelotDuLacβ€’3d ago
Apart from trichy getting surathkal and stuff.
hardcoreisdead
hardcoreisdeadOPβ€’3d ago
how much are u scoring
Opt
Optβ€’3d ago
I haven't checked
hardcoreisdead
hardcoreisdeadOPβ€’3d ago
pilani cse?
Opt
Optβ€’3d ago
Just gonna wait till Monday
SirLancelotDuLac
SirLancelotDuLacβ€’3d ago
Bro, you must have done advanced nicely 😭
Opt
Optβ€’3d ago
Everything except CSE according to last year's cut-off data
Opt
Optβ€’3d ago
No description
Opt
Optβ€’3d ago
I got 326
hardcoreisdead
hardcoreisdeadOPβ€’3d ago
take that and build your stack now bhaisahab general candidates 😭
Opt
Optβ€’3d ago
?? What
SirLancelotDuLac
SirLancelotDuLacβ€’3d ago
Again, the amount of lafdas I've heard about surathkal force me to consider other stuff.
hardcoreisdead
hardcoreisdeadOPβ€’3d ago
not for bits but govt ones
SirLancelotDuLac
SirLancelotDuLacβ€’3d ago
Damn, I should have given other exams too 😭
Opt
Optβ€’3d ago
Yeah I'm also General candidate. Pain. I'm still worrying about IAT result
hardcoreisdead
hardcoreisdeadOPβ€’3d ago
aur bhi ache options honge
Opt
Optβ€’3d ago
I half want to check score and half just want to wait
hardcoreisdead
hardcoreisdeadOPβ€’3d ago
theres dtu ofc but 99.9%iler deserves more
Opt
Optβ€’3d ago
Me with 99.4:
hardcoreisdead
hardcoreisdeadOPβ€’3d ago
wait it out ig
Opt
Optβ€’3d ago
Not results. Candidate responses and answer key are out
SirLancelotDuLac
SirLancelotDuLacβ€’3d ago
Lmao, I was just filling the dtu form ;_;
Opt
Optβ€’3d ago
What's dtu?
hardcoreisdead
hardcoreisdeadOPβ€’3d ago
delhi technological university
Opt
Optβ€’3d ago
Ah
hardcoreisdead
hardcoreisdeadOPβ€’3d ago
you should consider that btw
SirLancelotDuLac
SirLancelotDuLacβ€’3d ago
Sorry for asking, but did you see the probability question in paper 1?
hardcoreisdead
hardcoreisdeadOPβ€’3d ago
dtu cse is pretty good
Opt
Optβ€’3d ago
No interest in engineering so let's see Idr
SirLancelotDuLac
SirLancelotDuLacβ€’3d ago
The 19/60 vs 13/36 one? Ah.
hardcoreisdead
hardcoreisdeadOPβ€’3d ago
W guy
Opt
Optβ€’3d ago
I haven't looked at the Adv papers again after stepping out of the lab on the 18th I do not want to rememberπŸ™
hardcoreisdead
hardcoreisdeadOPβ€’3d ago
alrr closing this now
Opt
Optβ€’3d ago
Okie
hardcoreisdead
hardcoreisdeadOPβ€’3d ago
best of luck to everyone
Opt
Optβ€’3d ago
Good luck mate
SirLancelotDuLac
SirLancelotDuLacβ€’3d ago
Yea man. Also all the best for this year. πŸ™
hardcoreisdead
hardcoreisdeadOPβ€’3d ago
thanx a lot +solved @SirLancelotDuLac @Augustine
iTeachChem Helper
iTeachChem Helperβ€’3d ago
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