capacitor cube
given is a cube where each line has a capacitor of capacitance C. we need to find capacitance along specified points
67 Replies
@Gyro Gearloose
Note for OP
+solved @user1 @user2... to close the thread when your doubt is solved. Mention the users who helped you solve the doubt. This will be added to their stats.i was able to get C17 and c13 by symmetry and stuff
stuck at c14
Superposition works ig
kirchoffs laws?
like basics?
Gods no
That's a death sentence
living hell on earth
Ok superposition will be annoying.
Some folding should work. Lemme get a book
lol
our teacher never taught us how to do cube questions he was just like "its complicated just remember the result"
bro people just mug results
things like this you dont do in exams xD
maine toh kirchoffs se hi kiya hai
it is painful
but
yeha
you remember :P
no i mean if its very long and manual
it shouldn't be an exam question at all
unless there's a clever insight that simplifies it
have you tried mirror and folding symmetry?
did that help
i tried to fig out symmetrical current flow but it got complicated
like its ever gonna come in advance or mains
Check if this works.
huh
wow that's clever
looking for equipotential points
god damn this is correct
itni jaldi kaise
trying to combine the points is messing with my brain did you just wing it or follow a system
I remember one of my teachers mentioning it when another student asked a doubt
?? Wdym
nvm nvm
Well, you can try visualising
i was having trouble visualizing it
i got it now
Pinching the frame
I'm pretty sure you can do this with superposition too wait
I wanna try
uske baad explain bhi karna how u got it
Nvm I guess that only works for resistors
Im getting 9C/5
I mean, there's nothing stopping you except the time constraint.
how long would you estimate kirchoff's rules would take for this
I wouldn't hazard a guess
na your way is the best way
equipotential surfaces, shorting
@Opt does every sort of electrical symmetry just arrive from equipotential points?
mirror, folding
Ye
wowie
I never learnt those techniques per se because equipotential points se kaam ho jata hai
yeah you were essentially doing the same thing
There are weird cases where you have to break a node but that's rare
a node as in an intersection right? that happens in mirror symmetry
did u consider symmetry like this ?
he did the same thing but for 2/5 instead of 1/6
Yes
oh wait nvm
sorry im tripping
No, that's the plane
no i mean
if you tilted the plane 90 degree inward toward yourself
that's another symmetry
No it isn't.
?
oH
6 and 1 are not
equipot
?
Because of the two nodes between which we have our p.d.
symmetry we obtain in such a way that the battery (here imaginary) is cut too
Ok, I really need to have lunch. Ping if needed.
the ends connecting it
will do
ah yeah yeah
gotchu
also @hardcoreisdead good job on your doubts man
some of the 2025 people have a server
just a friend group
and we were deadass like "bro hardcoreisdead asks such good doubts its demotivating"
💀 lolol
thanx
literal 99 percentilers by the way
ill take that as a compliment
ill close this by today night. gotta attend some classes
I second this :) well done @hardcoreisdead on grinding
Fr.
Hardcoreisdead doubt is equivalent to a humbling
Thanxx.
Miles more to go
@Opt does this work for finding C across 17
i considered a plane of symmetry 1674
2,4,5 are equipotential.
3,6,8 are equipotential.
So it's going to be 3 capacitors in parallel from 1 to node a, six in parallel from node a to node b, then three in parallel from node b to 7.
yes i solved usin that approach previously. trying out something different here
I'm not too familiar with using symmetry
ohh
no prob ill try again
5,2 and 4 are equipontential tho no?
Symmetry would mean from the perspective of 1 (if you're finding out b/w 1 and 7), 4,2 and 5 are equivalent or symmetric [adjacent]; after that 6,8,3 are symmetric [across face diagonal] and so on ig. We don't necessarily consider geometric symmetry iirc. (Symmetry here means the one with equipotential points wali thing)
they are and i did using that in another method
exploring planes of symmetry
to find these points current division has to be
in 1 and 7 its easy
gets a bit tedious with 1 and 3
got em all solved
thanx everyone
+solved @Opt @SirLancelotDuLac @Nimboi
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