Vectors algebra
The resultant of P vector and Q vector is perpendicular to P vector what is the angle between P vector and Q vector
Pls help me with the diagram
11 Replies
@Apu
Note for OP
+solved @user1 @user2... to close the thread when your doubt is solved. Mention the users who helped you solve the doubt. This will be added to their stats.$$\vec{p}\cdot(\vec{p}+\vec{q})=0$$
$$\lvert\vec{p}\rvert^{2}+\lvert\vec{p}\rvert\lvert\vec{q}\rvert cos\theta = 0$$
$$\implies cos\theta = -\frac{\lvert\vec{p}\rvert}{\lvert\vec{q}\rvert}$$
Opt
Theta is the angle between p and q vectors.
Of course, I assume p is not the zero vector
Is this not showing q-p ?
Oh right ;_;
Place three vectors in a right angled triangle in a cyclic way and flip one of the two perpendicular vectors. The hypotenuse is q (say) and one of the perpendicular sides is p, while the remaining side is (p+q)
Something like this?
I've transposed q parallel to itself so no change.
just assume
p = i
q = j - i
diagram should be fairly easy with this assumption, but hmu if you want more help
oh thx guys
+solved @Opt @SirLancelotDuLac @Captain Cool
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