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@Apu
Note for OP
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Let tan(2theta)=12/7, then 2t/(1-t²)=12/5. Solve this quadratic to get tan(theta) and hence theta
Achcha haa okok
Yea I've done something wrong haven't i

Factorization seems incorrect. 6t^2+5t-6=6t^2+9t-4t-6=(3t-2)(2t+3)=0
Since the given expression must be +ve, the required value is arctan(2/3)
AAAAAAAAA WATTT
Yea dude I'm too high on this shit thanks a lot
+solved @SirLancelotDuLac
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