Momentum conservation
momentum consv means acceleration of centre of mass is zero, so i want to confirm it in this case...
at the top point when it comes to rest:
1. if we consider both wedge and block(we see the com of both of them), then both the normals cancel out and net force on com in x axis is zero so mom is consv in x axis.
2. if we only consider the block(we only see the com of the block), then there is nothing that balances the normal on the block(or it's com), hence can we say momentum is not conserved in x axis??
[ofcourse it's not consv in y axis that's clear to me]
6 Replies
@Gyro Gearloose
Note for OP
+solved @user1 @user2... to close the thread when your doubt is solved. Mention the users who helped you solve the doubt. This will be added to their stats.Momentum of individual body is not conserved but since normal is a internal force if we consider block and wedge as a system the normal cancles out and we can say that the momentum of whole system is not conserved
alright thanks, that's what i needed to know too
+solved @Real potato
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