10 Replies
@Gyro Gearloose
Note for OP
+solved @user1 @user2... to close the thread when your doubt is solved. Mention the users who helped you solve the doubt. This will be added to their stats.initial charge on top capacitor is c(e1-e2) and bottom one is ce2
initial potential energy of system = c/2 (e1^2 +2e2^2 -2e1e2)
now when switch is opened i am somehow getting zero charge flow through e1 thus initial = final potential energy , work done by battery = 0 , heat generated = 0
can some1 confirm the ans
anyone...?
Ope nvm
This is all I have
can u share some working
For?
when u apply kvl the second time
the E2 is disconnected
but theres already some charge on the capacitors
It's a single loop. E2 doesn't play any role na?
ig u didnt consider those