electrostatic shielding

ignore this image , check below for actual ques
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49 Replies
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@Gyro Gearloose
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CorrodedCoffin
CorrodedCoffinOP4mo ago
cant we say f1= f2=f3=0 by electrostatic shielding
flower
flower4mo ago
ye nahi padha hai bro
CorrodedCoffin
CorrodedCoffinOP4mo ago
shielding nahi hua abhi?
flower
flower4mo ago
nahh i think agli ki classes me yahi karwaenge
CorrodedCoffin
CorrodedCoffinOP3mo ago
anyone...?
Nimboi [ping if answering]
induced charges i think have you studied charge induction in conductors? but they specifically said large distance r and charge on conductor is 0 so now im not sure anymore nvm
CorrodedCoffin
CorrodedCoffinOP3mo ago
yes i did mere logic se toh zero aa rha sab
Opt
Opt3mo ago
Just a sec, what are F1, F2, F3?
CorrodedCoffin
CorrodedCoffinOP3mo ago
ill update the ques
CorrodedCoffin
CorrodedCoffinOP3mo ago
No description
CorrodedCoffin
CorrodedCoffinOP3mo ago
No description
CorrodedCoffin
CorrodedCoffinOP3mo ago
,rotate
TeXit
TeXit3mo ago
No description
CorrodedCoffin
CorrodedCoffinOP3mo ago
Aisa distribution hoga mere khayal se Outermost surface jispe qb+qc charge hai uski charge density qd pe depend karegi qd pe qb ek force lagayega and qc ek force lagayega uska exact opposite force charge induced on sphere lagayega
Imine
Imine3mo ago
hm shouldnt force on q1 and q2 be 0 and qd pe k(qb+qc)/r^2
CorrodedCoffin
CorrodedCoffinOP3mo ago
yep kaise what even is q1
Imine
Imine3mo ago
mb i meant jo dono charges hai sphere me
CorrodedCoffin
CorrodedCoffinOP3mo ago
why tho
Opt
Opt3mo ago
I'm guessing B? Sorry about the delay
CorrodedCoffin
CorrodedCoffinOP3mo ago
yeah B
Opt
Opt3mo ago
So what's the doubt?
CorrodedCoffin
CorrodedCoffinOP3mo ago
f3 kya hoga
coolguy.
coolguy.3mo ago
its easy but if you really want an explanation
coolguy.
coolguy.3mo ago
purcell has one
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No description
Opt
Opt3mo ago
F3 will be coulomb force na?
CorrodedCoffin
CorrodedCoffinOP3mo ago
i think i get it now correct me if i am wrong andar jo charge hai qb and qc unka force is exactly the opposite of the force of charges induced in the cavity. thus cavity mein induced charge and cavity ke andar ka charge has no effect in outerworld however the charges induced on the bigger sphere will have a force on the external particle damn.
Opt
Opt3mo ago
Yup. Wait, you hadn't got that? I thought you were moving forward with that fact and I was confused as to what else you wanted to know. 🤦‍♂️ Sorry mate
CorrodedCoffin
CorrodedCoffinOP3mo ago
this concept made my brain melt today dude
Opt
Opt3mo ago
I suggest reading Griffiths for this one concept. Even if just for this. Griffiths made it really clear to me And not with maths either Through logic
CorrodedCoffin
CorrodedCoffinOP3mo ago
can u share pdf or photos (its clear now but still ) the entire conductors part theoretical questions
Imine
Imine3mo ago
https://nucleares.unam.mx/~martinel/griffiths_4ed.pdf what can we say bout their magnitudes if the charges werent at centre
coolguy.
coolguy.3mo ago
It'll remain the same Irrespective of the positioning of the charge inside the cavity
Imine
Imine3mo ago
No description
coolguy.
coolguy.3mo ago
Ooh
Imine
Imine3mo ago
yeahh
coolguy.
coolguy.3mo ago
Lemme read again thank you tho 😭
Imine
Imine3mo ago
cuz charge density would would be diff and they wont cancel each other out
coolguy.
coolguy.3mo ago
Hmm so if it were off centre there would exist some field at the centre of the cavity I don't understand this I mean if it were off centre then it would be attracted to the boundary of the cavity But what logic has he given
Imine
Imine3mo ago
yep when it is at centre, it induces -Qb on surface, distributed uniformly so negative charge elements on a diameter cancel each other out
coolguy.
coolguy.3mo ago
I don't get this line: "The charge therefore doesn't change the fact that electric field is zero at the centre"
Imine
Imine3mo ago
i mean there would be more charge density on the part of the boundary its near to so more attraction
coolguy.
coolguy.3mo ago
This line though :((
Imine
Imine3mo ago
arre this just means ki before Qb was there, field was zero at centre...and afterwards too, when Qb is placed at centre field is still 0
coolguy.
coolguy.3mo ago
I meann it makes sense cause F=qE so E is zero Bohot confusing karke likhte hain :') Thank you again for pointing it out warna I would stick to the wrong concepts
Imine
Imine3mo ago
np np
CorrodedCoffin
CorrodedCoffinOP3mo ago
+solved @Opt @coolguy.
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