77 replies

typescript simplify a type guard

const validationResult = UserLoginSchema.safeParse(req.body);

    if (
        validationResult.error instanceof ZodError ||
        validationResult.data === undefined
    ) {
        res.status(400).json(validationResult.error);
        return;
    }

    const { name, password } = validationResult.data;

const validationResult = UserLoginSchema.safeParse(req.body);

    if (
        validationResult.error instanceof ZodError ||
        validationResult.data === undefined
    ) {
        res.status(400).json(validationResult.error);
        return;
    }

    const { name, password } = validationResult.data;

const validationResult = UserLoginSchema.safeParse(req.body);

    if (
        validationResult.error instanceof ZodError ||
        validationResult.data === undefined
    ) {
        res.status(400).json(validationResult.error);
        return;
    }

    const { name, password } = validationResult.data;

const validationResult = UserLoginSchema.safeParse(req.body);

    if (
        validationResult.error instanceof ZodError ||
        validationResult.data === undefined
    ) {
        res.status(400).json(validationResult.error);
        return;
    }

    const { name, password } = validationResult.data;

I have this code. I want the if statement to be able to verify that

validationResullt.error

validationResullt.error

validationResullt.error

validationResullt.error is a

ZodError

ZodError

ZodError

ZodError and

validation.data

validation.data

validation.data

validation.data is not undefined but there doesn't seem a way to do them in one statement.

should I use

as

as

as

as to explicitly assert the type of

validation.data

validation.data

validation.data

validation.data? I don't want another if statement because it would just duplicate the logic inside first if

typescript simplify a type guard

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