Electric potential wrt. equilibrium

uhm so i tried to think equilibrium basis on this and lets just say one was right and other came incorrect so i need help as to how equilibrium effects electric potential
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20 Replies
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coolguy.
coolguy.3mo ago
Basically depends on the overall sign of the circled part
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coolguy.
coolguy.3mo ago
E0 - something +ve< E0
Sephrina
SephrinaOP3mo ago
yeah i do know the nernst equation thingy
coolguy.
coolguy.3mo ago
And vice versa
Sephrina
SephrinaOP3mo ago
but like say i had the chnge only in h+ conc then how would i do?
coolguy.
coolguy.3mo ago
Accha Woh Q ka expression you write Usme bas H+ ka value change kardo
Sephrina
SephrinaOP3mo ago
say here it is inverse relation
coolguy.
coolguy.3mo ago
If you wanna feel it see how the eqn is behaving upon increasing or decreasing H+
Sephrina
SephrinaOP3mo ago
to log ke baad wala chiz intutive nhi hota
coolguy.
coolguy.3mo ago
You mean Q right
Sephrina
SephrinaOP3mo ago
ys
coolguy.
coolguy.3mo ago
Intuitive hota toh hai lemme think Le chatliers principle se explain kar sakte hain I'll write a nice para and come
Sephrina
SephrinaOP3mo ago
yh like agar mera h+ conc say yaha inverse realated hai to just by tht mai kaise jaanu ki mera logQ kaise alter hoga tht is my question ypp sureeee
coolguy.
coolguy.3mo ago
Haan right you want to understand it
Sephrina
SephrinaOP3mo ago
yh
coolguy.
coolguy.3mo ago
It's like providing more raw material for production, we know that H+ is a reactant (hence the inverse relation), jitna jyada reactant utna forward bhadega rxn, aur utna jyada greater hoga cell potential With this you can compare a) and b) and defo a) ka cell potential is greater than b) ka cell potential Now, to know if potential is less than or greater than E0, You must see if Q<1 or Q>1, isme you need precise value as E0 is also a numerical value Noice Comparison b/w a) and b) is possible eqm ko samajhkar, but to tell it is less than or greater than E0 , you need to calculate Isse zyada sir explain kar denge Wrote what I think
Sephrina
SephrinaOP3mo ago
+solved @coolguy.
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