haloalkanes and arenes
im having trouble in these types of questions. what should be the right thinking to do these
55 Replies
@Dexter
Note for OP
+solved @user1 @user2... to close the thread when your doubt is solved. Mention the users who helped you solve the doubt. This will be added to their stats.read up on properties of SN1 and SN2 and read up ncert
For the rate of solvolysis question, you should consider the stability of the formed carbocation
Think of the hyperconjugative hydrogens
yaha solvolysis kaha hai?
SN1
Solvolysis hi hoti hai
ye to naya pata chla
🤡
Solvent acting as a nucleophile in most cases
Lmao not something important
aur sn1 wale me to u can see realtive stability of the benzyl one here to get ans
Yeah exactly
20. Vala ajeeb hai
Gotta see what that is about
kyu?
Wouldn't all of them give you a good enough yield
ncert me i think tha which one is best of yeild
let me see
aemm ncertt
It asked "not"
oohh.....
Multiple methods give you satisfactory yield
Which one doesn't is the question
And mere hisab se saare hi de rahe hain
The ones I think could be the answer are a) and d)
'cause d) is radical based
Could give you mixed products
vahi
a) requires an extra step
a will give kyunki vaha water will become a good leaving grp
Protonation
and the halide will be added
tht will be the rds
but yeild to in end dekhte hai after equilibrium is established
That's alright
But the thing I'm confused about is if H3PO4 is strong enough
its is considered strong
I think it should be
But thoda doubt hai idk why
Will check pka to be sure
yps
2.14
It's good enough yaar
I'll have to think thoda sa is question me
i think d hi hoga
Haan lag vahi raha hai
'cause radical hai
yp same here
Could go into multiple pathways
h3po4 ensures ki oh- substitution doesnt happen right
But I feel like I should be more sure
kyunki NaI impossible hai bad yeild me
and PI3 is also good yelid giver
Yeah it would I guess
Vo to method hi uske liye hai
Upar se SN2
Facilitated by Acetone
h3po4 basically will protonate the alc and give h2o as leaving grp and give u carbcation
exactly
Badhiya solvation by Na+
Not exactly but yeah
yh finkelstein right
kyu?
Rearrangement nahi hota isme 'cause direct attack karke nikaalta hai I negative
Primary centre hai na?
SN1 kaise hoga
yh sn2 hoga na
Yup I guess vahi tha
ys
i seriously need to revise SN1 and SN2
Hmm koi ni kar lena
itna confusing to jab padha tha tab nhi laga tha
There are some really good sources
There's this channel called Victor Organic Chemistry Tutor
karengge karenge abhi
UAA
UGA
UAG
He has a whole playlist for substitution and elimination
AAHHH yess i watch them
Karo lmao
NICEEE
bhai ye 19th vala ek bar ache se smjha do
@Varun_Arora
answer A ha
See
Jis benzene ring pe CH3 laga hai CH2--Br ke opposite me
Usme 3 hyperconjugative hydrogens hain
3rd vaale me 2
Or vaise hi 4th vaale me 1
And 1st vaale me zero
Jitne jyada hyperconjugative hydrogen
Utna jyada stable carbocation
Utni badhiya SN1
Got it?
oh achaa
thanks bhai
if solved do close the doubt with tagging whos solved
+solved @Sephrina @Varun_Arora
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