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@Apu
Note for OP
+solved @user1 @user2... to close the thread when your doubt is solved. Mention the users who helped you solve the doubt. This will be added to their stats.
For the starting I multiplied the 2nd equation by 2 and then subtracted it to the first equation so that I could apply this identify
And only values of x y z satisfying by my method is x=4 y =2 z=1
Plug the results you got (y and z in terms of x) in the first equation and then you get the answer.
Wait what is the doubt, I'm sorry?
from what i did i am getting x=n,y=n/2,z=n/4
to make all of them integers i put x=4
and from that i get x=4 y =2 z= 1 which satifies the equation in the question
but i think there could be an better method than this no?
because i have to guess
can you think of an better way?
Once you get the above put the value of x,y and z in terms of n to get n²+4(n²/4)+16(n²/16)=48 and then get n= + or -4
Oo I get it noww
Thanksss!
+solved @SirLancelotDuLac
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