Current electricity
I often have trouble in using KCL in such qs. While writing the eqn, the teacher directly equated the current passing through each of the resistors to 0. I don't get why this works. I've seen this being used in other qs too... this maybe really silly, but yeah. Like why do we ignore the current through the cells?
And another question. In such qs what's the fastest method to solve them out of the many options available (kvl, kcl, superposn, thevenin...)>
4 Replies
@Gyro Gearloose
Note for OP
+solved @user1 @user2... to close the thread when your doubt is solved. Mention the users who helped you solve the doubt. This will be added to their stats.He is just stating that sum of currents entering leaving leaving a junction is zero, which is KCL
And here he has used nodal analysis, with enough practice nodal analysis is great
Though always keep classic procedures mastered
hmm okay
no like i was wondering how did he directly write the current in the 3rd arm as the current pasing through the upper 5 ohm and lower 5 ohm reistors