Force by wall
i am ok in first part but the second part? i dont get how to get the forces, one will be contact force, and there will be gravi also but how?
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@Gyro Gearloose
Note for OP
+solved @user1 @user2... to close the thread when your doubt is solved. Mention the users who helped you solve the doubt. This will be added to their stats.Fbottom + Fwall= mg
We know mg and Fbottom
Usse aajayega
Ye sab vectors hain btw
can u shw the fbd?
Sorry msg dekha hi nahi ðŸ˜
Fbd yaar wohi hoga har point par normal rxn banado wall par
Jo net reaction hoga woh Mg(vector)-Fbottom(vecto) hoga
Jo ya toh neeche ya toh upar hai
smj nhi aaya
Kuch aisa ban jata hai
Water ko ek separate object Maan lo
Aur uska fbd likh do
Resnick haliday mei they do this a lot
But haan Basically saare forces ka sum on the water is zero cause water in equilibrium
Ig 75 N hai ans?
nope
1N
Accha shayad calc error
Damn I forgot to take atmospheric pressure under consideration in fbd
That's why they gave top surface area
The weight of the water+the atmosphere exerting pressure at the top is balanced by the vertical component of force exerted by vertical walls+force by the bottom. So, rho.V.g+P_atm.(top area)=Patm(bottom area)+rho.g.h(bottom area)+(F by side walls in upward directions)
Thus, required force is F=rho.g.V-rho.g.h(Bottom area)=rho.g(V-(bottom area).h)=10^3.10(500-400).10^(-6)=1N
I don't have pen and paper, so sorry for the lack of diagram ;;
kinda got it
kinda not
OK OKKKKK GOT IT now i was taking the vector at complete horizontal thts why i wasnt getting
it will have some angle okey
+solved @SirLancelotDuLac @coolguy.
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