iTeachChem•7mo ago

How I can find the argument

│yt-satya-maths

iTeachChem Helper•6/15/25, 12:02 PM

@Apu

iTeachChem Helper•6/15/25, 12:02 PM

Note for OP

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coolguy.•6/15/25, 12:20 PM

Is answer c?

coolguy.•6/15/25, 12:20 PM

Nvm

coolguy.•6/15/25, 12:21 PM

Tho it's easy gimme a sec

coolguy.•6/15/25, 12:42 PM

Okay so I got c again and I realised you don't need to calculate only

coolguy.•6/15/25, 12:42 PM

The denominator is purely imaginary and numerator is purely real, hence option c is correct

coolguy.•6/15/25, 12:43 PM

Calculating involves locus

Ccoolguy.The denominator is purely imaginary and numerator is purely real, hence option c...

GUTXSOP•6/15/25, 12:44 PM

Hn. I know but how I can find argument

Ccoolguy.Is answer c?

GUTXSOP•6/15/25, 12:44 PM

Yes

GGUTXS Hn. I know but how I can find argument

coolguy.•6/15/25, 12:45 PM

Which means the answer is some -xi

coolguy.•6/15/25, 12:45 PM

X is positive

coolguy.•6/15/25, 12:45 PM

Do you know about the argand plane

coolguy.•6/15/25, 12:45 PM

You plot coefficient of iota on the y axis

coolguy.•6/15/25, 12:46 PM

And the real part on the x axis

Ccoolguy.You plot coefficient of iota on the y axis

GUTXSOP•6/15/25, 12:46 PM

Hnn ok I get it

coolguy.•6/15/25, 12:46 PM

Here real part is zero, and coefficient of iota is negative

coolguy.•6/15/25, 12:46 PM

That means the line is pointing downward

coolguy.•6/15/25, 12:46 PM

Argument is hence -pi/2

GUTXSOP•6/15/25, 12:47 PM

Hnn I get it thanks

coolguy.•6/15/25, 12:47 PM

Np :)

IiTeachChem Helper Empty message

CertifiedBrownMunda•6/16/25, 8:44 AM

This is solved right? OP kindly do this

How I can find the argument

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