I
iTeachChem•3mo ago
GUTXS

How I can find the argument

#🧠│yt-satya-maths
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10 Replies
iTeachChem Helper
iTeachChem Helper•3mo ago
@Apu
iTeachChem Helper
iTeachChem Helper•3mo ago
Note for OP
+solved @user1 @user2... to close the thread when your doubt is solved. Mention the users who helped you solve the doubt. This will be added to their stats.
coolguy.
coolguy.•3mo ago
Is answer c? Nvm Tho it's easy gimme a sec Okay so I got c again and I realised you don't need to calculate only The denominator is purely imaginary and numerator is purely real, hence option c is correct Calculating involves locus
GUTXS
GUTXSOP•3mo ago
Hn. I know but how I can find argument Yes
coolguy.
coolguy.•3mo ago
Which means the answer is some -xi X is positive Do you know about the argand plane You plot coefficient of iota on the y axis And the real part on the x axis
GUTXS
GUTXSOP•3mo ago
Hnn ok I get it
coolguy.
coolguy.•3mo ago
Here real part is zero, and coefficient of iota is negative That means the line is pointing downward Argument is hence -pi/2
GUTXS
GUTXSOP•3mo ago
Hnn I get it thanks
coolguy.
coolguy.•3mo ago
Np :)
CertifiedBrownMunda
CertifiedBrownMunda•3mo ago
This is solved right? OP kindly do this

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