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@Apu
Note for OP
+solved @user1 @user2... to close the thread when your doubt is solved. Mention the users who helped you solve the doubt. This will be added to their stats.Differentiability hui nahi yar abhi meri
@SirLancelotDuLac hi how would we do this
write cos2x/3^k in terms of sin applying half angle formula then youll be able to form sin3theta form, then apply limit k tending towards infinity on the pi notation
and youll be able to find out what f(x) is
Apologies for the crappy handwriting, but the terms in the product above cancel out to give sin(x) in num. and sin(x/3^n) in denominator. As for the denominator, it tends to 3^n. Applying sine approximation sin(x/3^n).3^n tends to x.
ahhh thanks
kk understood
+solved @SirLancelotDuLac
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