RC problem
V-i(Ro +kt)-q/c=0 (from KVL)
differentiate , rearrange , integrate to get i as function of time
i get i= VR/(R+kt)^2
heat = integration i^2Rdt
work done = integration Vidt
my process seems flawless but i constantly get 26/27. some1 pls check
13 Replies
@Gyro Gearloose
Note for OP
+solved @user1 @user2... to close the thread when your doubt is solved. Mention the users who helped you solve the doubt. This will be added to their stats.all of this is basically what i did
Ohkay mai karke dekhta hun ðŸ˜
Okay no idea sorry…….
ðŸ˜
I got this, is this correct?
Heat mein (Ro+kt) ki power 4 nahi integrate hogi
Also I am getting work done as v^2/3k
one alternate soluton i got was finc q as func of t .
q= VCkt / Ro+kt
now find q at 2Ro/k . q= 2VC/3
now, Ui+ Wb = Uf + H
Ui=0 , Wb = qV , Uf = q^2 /2c , H= Wb-Uf
H/Wb = 1- Uf/Wb = 2/3
much more easier
still wanna know mera current se kyu nahi aaya
Ig u integrated wrongly, there wont be a any 2 in denom
oh shit right
what bout this
Ig if u define instantenous heat then it would equal resistance at tht time * current at tht time^2 so there would ve a (R0+kt)^4 term in denom but after multiplting by resistance which is R0+kt u would just get (R0+kt)^3 in denom
right
big thanx
+solved @integralofe^2x
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